Answer:
Option C
Explanation:
Water present in first mixture $=\frac{2\times12}{100}=\frac{6}{25}$litres
Water present in second mixture $\frac{3\times5}{100}=\frac{3}{20}$
Total water present in 5 litres of the resulting mixture$=\frac{6}{25}+\frac{3}{20}=\frac{39}{100}$
Pertange of water present in the resulting mixture $=\frac{\frac{39}{100}\times 100}{5}=7\frac{4}{5}%$