Percentage | Arithmetic aptitude | Discussion Page

A gets 10% more marks than B. Then B gets

A) 10% less marks than A

B) 10% more marks than A

$9\left(\frac{1}{11}\right)$ % marks less than A

D) Cannot be determined

Option C

If B gets 100 marks, then A gets 110 marks.

B got $\left(\frac{10}{110}\right)\times 100$ $= \left(\frac{100}{11}\right)$ $= 9 \left(\frac{1}{11}\right)$ % marks less than A

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