1) The ratio of the ages of a man and his wife is 4 : 3. After 4 years, this ratio will be 9 : 7. If at the time of marriage, the ratio was 5:3, then how many years ago were they married ? A) 8 years B) 10 years C) 12 years D) 15 years Answer: Option CExplanation:Let the present ages of the man and his wife be 4x and 3x years repectivelythen , $\frac{4x+4}{3x+4}= \frac{9}{7}$$=>7(4x+4)=9(3x+4)$$=>x =8$So their present ages are 32 years and 24 years respectively .Suppose they were married z years agoThen $\frac{32-z}{24-z}=\frac{5}{3}$$=>3(32-z)=5(24-z)$$=>2z =24$$=> z=12$
