Discussion Forum

Three equal cubes are placed adjacently in a row.Find the ratio of total surface area of the neww cuboid to thaat of the sum of the surface areas of the three cubes.

Answer:

Explanation:

Let x cm be the edge of 3 equals cubes.

Surface area of 3 equal cubes $=3(6x^{3})=18x^{2}$

Lenght of the resulting cuboid=3x cm

Breadth=x cm and height=xcm

Total surafce area of the cuboid=2(lb+bh+hl) $=2(3x^{2}+x^{2}+3x^{2}=14x^{2}$

Required ratio$\frac{14x^{2}}{18x^{2}}=\frac{7}{9}$