1) If $1^{3}+2^{3}+..........+9^{3}=2025 then the value (0.11)^{3}+(0.22)^{3}+......+(0.99^{3})$ is close to A) 0.2695 B) 0.3696 C) 2.695 D) 3.695 Answer: Option CExplanation:$(0.11)^{3}+(0.22)^{3}+.......+(0.99)^{3}=(0.11)^{3}(1^{2}+2^{2}+......+9^{2})$ $0.001331\times2025=2.695275= 2.695$
