1)

Find the least number which when divided by 16, 18, 20 and 25 leaves 4 as remainder in each case, but when divided by 7 leaves no remainder.

A) 17004

B) 18000

C) 18002

D) 18004

**Answer:**

Option D**Explanation:**

Take LCM of 16, 18, 20 and 25 = 3600.

Now the required number will be the order of (3600 x K) + 4 which is divisible by 7.

By hit and trial method find out the least value of K , in this case K=5.

So the answer is (3600 x 5) + 4 = **18004**