1) If two numbers are respectively 30% and 40 % more than a third number ,what the percent is the first o the second ? A) 85% B) $92\frac{6}{7}$ % C) $92\frac{7}{6}$ D) $79\frac{6}{7}$ E) $92\frac{7}{6}$ Answer: Option BExplanation:Let $3^{rd}$ number = 100 Then $1^{st}$ and $2^{nd}$ numbers are 130 and 140 First as a percentage of second $= \left(\frac{130}{140}\right)\times 100$ = $92\frac{6}{7}$%
