1)

A man loses 12 $\frac{1}{2}$% of his money and after spending 70% of the remainder, has Rs 210 left. At first the man had?

 


A) Rs.880

B) Rs.720

C) Rs.800

D) Rs.600

E) Rs. 850

Answer:

Option C

Explanation:

Let the man at first had = Rs.x

Money lost $= \frac{25}{2}$% of $x = \frac{25x}{(2\times 100)}$ $=\frac{x}{8}$

Balance money $= x– \frac{x}{8}$ $=\frac{7x}{8}$

Money spent $= \left(\frac{70}{100}\right) \times \left(\frac{7x}{8}\right)$ $= \frac{49x}{80}$

Money left $= \left(\frac{7x}{8}\right)-\left(\frac{49x}{80}\right)$ $= \frac{21x}{80}$

Given, $\frac{21x}{80} = 210$

x = Rs.800