Discussion Forum



1)

The present ages of three persons are in proportions 4:7: 9. Eight years ago, the sum of their ages was 56. Find their present ages (in years).


A) 8, 20, 28

B) 16. 28. 36

C) 20, 35, 45

D) None of these

Answer:

Option B

Explanation:

Let their present ages be 4x,7x and 9x years repectively
Then (4x-8)+(7x-8)+(9x-8)=56
=> 20x = 80
=> x= 4
Their present ages are 16  years, 28 years and 36 years respectively