Discussion Forum

Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other in 23 seconds. The ratio of their speeds is :

Answer:

Explanation:

Let the speeds of the two trains be $x$ m/sec and $y$ m/sec respectively. Then, length of the first train $=27x$ meters, and length of

the second train $=17y$ meters.

$\therefore \frac{27x+17y}{x+y}=23$

$\Leftrightarrow$ $27x+17y$ $=23x+23y$

$\Leftrightarrow 4x=6y$ $\Leftrightarrow\frac{x}{y}=\frac{3}{2}$.

So, the ratio of their speeds = 3:2.