Discussion Forum

A dog takes 4 leaps for every 5 leaps of a hare but 3 leaps of a dog are equal to 4 leaps of the hare. Compare their speeds.

Answer:

Explanation:

Let the distance covered in 1 leap of the dog be $x$ and that covered in 1 leap of the hare be $y$.

Then, $3x=4y$ $\Rightarrow x=\frac{4}{3}y$ $\Rightarrow 4x=\frac{16}{3}y$

Ratio of speeds of dog-and-hare = Ratio of distances covered by them in the same time

$=4x:5y$ $=\frac{16}{3}y:5y$ $=\frac{16}{3}:5$ = 16:15