Discussion Forum

If 6 men and 8 boys can do a piece of work in 10 days and 26 men and 48 boys can do the same work in 2 days, the time taken by 15 men and 20 boys to do the same type of work will be

Answer:

Explanation:

Given (6 Men +8 boys)$\times$10 = (26 men + 48 boys)$\times$2

60 men + 80 boys = 52 men  + 96 boys

1 man = 2 boys

15 men + 20 boys = 30 boys +20 boys = 50 boys

6 men + 8 boys = 12 boys + 8 boys = 20 boys

$\therefore$ 20 boys = 10 days

50 boys = $x$

$x=\frac{(20\times 10)}{50}$ = 4 days