1)

Match the transformation in Column I with appropriate options in Column II

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A) $(A) \rightarrow p,r,s ;(B) \rightarrow r,s ;(C) \rightarrow t, ;(D) \rightarrow p,q,t$

B) $(A) \rightarrow p,r,s ;(B) \rightarrow r,s ;(C) \rightarrow t, ;(D) \rightarrow t$

C) $(A) \rightarrow p,r,s ;(B) \rightarrow r ;(C) \rightarrow t, ;(D) \rightarrow p,t$

Answer:

Option A

Explanation:

(A)  $CO_{2}(s) \rightarrow  CO_{2}(g)$

It is just a phase transition (sublimation) as no chemical change has occurred. Sublimation is always endothermic. Product is gas, more disordered, hence $\triangle $ s  is positive

(B) $CaCO_{3}(s) \rightarrow   CaO(s)+CO_{2}(g)$

It is a chemical decomposition, not a phase change. Thermal decomposition occurs at the expense of energy, hence endothermic. Product contains a gaseous species, hence  $\triangle S>0$

(C) $2H \rightarrow H_{2}(g)$

A new H-H covalent bond is formed, hence, $\triangle H <0.$ Also, the product is less disordered than the reactant, $\triangle S  <0$

(D) Allohopes are considered as different phase, hence $P_{(white,solid)} \rightarrow  P_{red,solid)}$ transition as well as allotropic change.

Also. red phosphorus is more ordered than white phosphorus, $\triangle$ S< 0.