Discussion Forum



1)

In the given circuit, a charge of +80 $\mu C$  is given to the upper plate of the $4 \mu F$  capacitor. Then in the steady-state, the charge  on the upper  plate of the $3 \mu F$  capacitor is 

24112021751_m1.PNG


A) +32 $\mu C$

B) +40 $\mu C$

C) +48 $\mu C$

D) +80 $\mu C$

Answer:

Option C

Explanation:

 Between $3 \mu F $ and $2 \mu F$ (in parallel) total charge of $80 \mu C$ will distribute in direct ratio of capacity

9112021243_k11.PNG

 $\therefore$   $\frac{q_{3}}{q_{2}}=\frac{3}{2}$

 or       $q_{2}=\left(\frac{3}{3+2}\right)(80)=48 \mu C$