Discussion Forum

A student is performing the experiment of the resonance column. The diameter of the column tube is 4 cm. The frequency of the tuning fork is  512 Hz. The air temperature is $38^{0}C$  in which the speed of sound is 336 m/s. The zero of the meter scale coincides with the top end of the resonance column tube. When the first resonance occurs, the reading of the water level in the column is

Answer:

Explanation:

 With end correction

 $f=n\left[\frac{v}{4(1+e)}\right],$  where n=1,2,3....

$=n\left[\frac{v}{4(1+0.6r)}\right]$

 because e=0.6 r , where r is radius of pipe 

 for  first sentence ,n=1

 $\therefore$     $f=\frac{v}{4(l+0.6r)}$

 or     $l=\frac{v}{4f}-0.6r$

= $\left[\left(\frac{336 \times100}{4 \times 512}\right)-0.6\times2\right]cm$

=15.2 cm