Discussion Forum



1)

Identify the binary mixture(s) that can be separated into individual compounds, by differential extraction, as shown in the given scheme.

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A) $C_{6}H_{5}COH$ and $ C_{6}H_{5}COOH$

B) $C_{6}H_{5}COOH$ and $ C_{6}H_{5}CH_{2}OH$

C) $c_{6}H_{5}CH_{2}OH$ AND $C_{6}H_{5}OH$

D) $C_{6}H_{5}CH_{2}OH$ and $C_{6}H_{5}CH_{2}COOH$

Answer:

Option B,D

Explanation:

For separation be differential extraction one of the components must form salt with the given base so that the salt will be extracted in an aqueous layer leaving other components in organic layer.

(a) Both phenol and benzoic acid forms salt with NaOH, hence this mixture can't be separated

(b) Benzoic acid forms salt with NaOH while benzyl alcohol does not, hence the mixture can be separated. using NaOH. Also benzoic acid forms salt with NaHCO3 but benzyl alcohol does not, hence NaHCO3 can be used for separation.

(c) Neither benzyl alcohol nor phenol forms salt with NaHCO3, the mixture cannot be separated using NaHCO3.

(d)$C_{6}H_{5}CH_{2}COOH$forms salt with $NaOH,C_{6}H_{5}CH_{2}OH$  does not, hencemixture can be separated using$NaOH .C_{6}H_{5}CH_{2}COOH$ forms salt  with $NaHCO_{3},C_{6}H_{5}CH_{2}OH$  does not- hence mixture can be separated using $NaHCO_{3}$