Discussion Forum



1)

The shape of $XeO_{2}F_{2}$ molecule is 


A) trigonal bipyramidal

B) square planar

C) tetrahedral

D) see-saw

Answer:

Option D

Explanation:

In  $XeO_{2}F_{2}$  the bonding arrangement around the central atom Xe is 

11112021406_j5.PNG

 $\Rightarrow$  Hybridization of Xe=$sp^{3}d$

$sp^{3}d$  hybridization corresponds to trigonal bipyramidal geometry. Also, in trigonal bipyramidal geometry, lone pairs remain present on equatorial positions in order to give less electronic repulsion.

.11112021881_m1.PNG

Note According to Bent's ru1e, the more electronegative atoms must be present on the axial position. Hence, F is kept on axial positions.