Discussion Forum



1)

The reactions of Cl2  gas with cold-dilute and hot -concentrated NaOH in water give sodium salts of two (different)  oxoacids of chlorine, P and Q, respectively. The Cl2 gas reacts with SO2 gas , in the presence of charcoal, to give a product R. R reacts with  white phosphorous to give a  compound s, on hydrolysis, s gives an oxoacid of phosphorous T

 R, S and T respectively, are


A) $SO_{2}Cl_{2}, PCl_{5}$ and $H_{3}PO_{4}$

B) $SO_{2}Cl_{2}, PCl_{5}$ and $H_{3}PO_{3}$

C) $SO_{}Cl_{2}, PCl_{3} $and $H_{3}PO_{2}$

D) $SO_{}Cl_{2}, PCl_{5} $and $H_{3}PO_{4}$

Answer:

Option A

Explanation:

 Plan 2NaOH +Cl2  $\underrightarrow {cold}$    $NaCl+NaOCl+H_{2}O$

                                                                          P

$6NaOH+3Cl_{2}$  $\underrightarrow {hot}$   $5NaCl+NaClO_{3}+3H_{2}O$

                                                                Q

$HOCl$    $\underrightarrow {NaOH}$     $NaOCl$

hypochlorous                             P

acid

 $Cl_{2}+SO_{2}\rightarrow SO_{2}Cl_{2}$

                                             R

 $10SO_{2}Cl_{2}+P_{4}\rightarrow 4PCl_{5}+ 10SO_{2}$

                                               S

$PCl_{5}+4H_{2}O\rightarrow H_{3}PO_{4}+ 5HCl$

                                            T