1) In L-C-R circuit as shown below both switches are open initially. Now switch S1 and S2, are closed .(q is charge on the capacitor and $\tau$=RC is capacitance time constant) . Which of the following statement is correct? A) Workdone by the battery is half of the energy dissipated in the resistor B) At $t= \tau,q=CV/2$ C) $t= 2\tau,q=CV(1-e^{-2})$ D) $t= \frac{\tau}{2},q=CV(1-e^{-1})$ Answer: Option CExplanation:For charging of capacitor $q= CV(1-e^{t/\tau})$ at $t=2\tau\Rightarrow q=CV (1-e^{-2})$
