1)

A ray of light along  $x+\sqrt{3}y=\sqrt{3}$  gets reflected upon reaching x-axis , the equation of the reflected ray is


A) $y=x+\sqrt{3}$

B) $\sqrt{3}y=x-\sqrt{3}$

C) $y=\sqrt{3}x-\sqrt{3}$

D) $\sqrt{3}y=x-1$

Answer:

Option B

Explanation:

Take any point B(0,1) on gives line, equation of AB'

 $y-0= \frac{-1-0}{0-\sqrt{3}}(x-\sqrt{3})$

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$\Rightarrow$     $ -\sqrt{3}y=-x+\sqrt{3}$

 $\Rightarrow$     $ x-\sqrt{3}y=\sqrt{3}$

$\Rightarrow $     $\sqrt{3}y=x-\sqrt{3}$