1)

As an aqueous solution of metal ion M1 reacts separately with reagents  Q and R  in excess to give tetrahedral and square planar complexes, respectively. An aqueous solution of another metal ion M2  always forms tetrahedral complexes with these reagents. An aqueous solution of M2 on  reaction with  reagent S gives white precipitate  which dissolves in  excess of S. The  reactions are summarized in the scheme given below

2732021467_m10.PNG

Reagent S is 


A) $ K_{4}[Fe(CN)_{6}]$

B) $Na_{2}HPO_{4}$

C) $K_{2}CrO_{4}$

D) KOH

Answer:

Option D

Explanation:

Zn2+  on treatment with excess Of KOH produces  [Zn(OH)4]2-.