Answer:
Option A
Explanation:
Plan (i) The number of arrangement of m distinct objects is given by n!.
(ii) Probability =
NUmber of favourable outcomes/ Number of total out comes
Total number of ways to arrange 3 boys and 2 girls are 5!
According to given condition , following cases may be
BGGBB
GGBBB
GBGBB
GBBGB
BGBGB
So, number of favourable ways
= 5! x 3! x 2!
= 60
$\therefore$ Required probability
= $\frac{60}{120}=\frac{1}{2}$
