Discussion Forum

In which of the following reactions H₂O₂ acts as a reducing agent ?

I.  $H_{2}O_{2}+2H^{+}+2e^{-}\rightarrow2H_{2}O$

II.  $H_{2}O_{2}-2e^{-}\rightarrow O_{2}+2H^{+}$

III.  $H_{2}O_{2}+2e^{-}\rightarrow 2OH^{-}$

IV. $H_{2}O_{2}+2OH^{-}-2e^{-} \rightarrow O_{2}+2H_{2}O$

Answer:

Explanation:

 The release of electron is known as reduction. So H₂O₂ acts as reducing agent when it releases electrons.

 Here, in reaction (II)  and (IV), H₂O₂  releases two-electron hence,  reaction (II) and (IV)  is known as reduction.

   In reaction, (I) and (III)  two electrons are being added, so  (I) and (III) represents oxidation.