Discussion Forum



1)

In the Hofmann-bromamide degradation reaction, the number of moles of NaOH and Br2 used Per mole of amine produce are


A) 4 moles of NaOH and 2 moles of $Br_{2}$

B) 2 moles of NaOH and 2 moles of $Br_{2}$

C) 4 moles of NaOH and 1 mole of $Br_{2}$

D) 1 mole of NaOH and 1 mole of $Br_{2}$

Answer:

Option C

Explanation:

Hofmann-bromamide degradation reaction is given as:

$RCONH_{2}$ + $4NaOH$ + $Br_{2}$ $\rightarrow$ $RNH_{2}$ + $Na_{2}CO_{3}$ + $2NaBr$ + $2H_{2}O$

Hence, four moles of NaOH and one mole of are used.