Answer:
Option D
Explanation:
From Newton's second law, $\frac{\triangle p}{\triangle t}=F$
$\Rightarrow \triangle p=F\triangle t$
$\therefore$ $p=\int_{}^{}dp =\int_{0}^{1} F dt$
$\Rightarrow p= \int_{0}^{1} 6t dt=3kg(\frac{m}{s})$
Also , change in kinetic energy
$\triangle k= \frac{\triangle p^{2}}{2m}=\frac{3^{2}}{2\times 1}$
= 4.5
From work -energy theorm, work done = change in kinectic energy
So, work done = Δ k= 4.5 J
