Discussion Forum

3-methyl-pent-2-ene on reaction with HBr in presence of peroxide forms an addition product . The number of possible stereoisomers for the product is

Answer:

Explanation:

The number of stereoisomers in molecules which are not divisble into two equal halves and have n number of asymmetric  C-atoms = 2ⁿ

3-methyl-pen-2-ene on reaction with HBr in presence of peroxide forms an addition product  i.e,   2-bromo-3-methyl pentane. It has two chiral centres.   Therefore 4 stereoisomers are possible.