1)

If G(g) , H(h) and P(p)  are centroid orthocentre and circumcentre of a triangle and xp+yh+zg=0, then (x,y,z) is equal to 


A) 1,1,-2

B) 2,1,-3

C) 1,3,-4

D) 2,3,-5

Answer:

Option B

Explanation:

 We know that, orthocentre , centroid and circumcentre of a triangle are collinear and centroid  divides orthocentre and circumcentre in the ratio 2:1

 By using internally division. 

$\frac{2p+1h}{2+1}=g$

$\Rightarrow$                2p+h-3g=0

 But it is given xp+yh+zg=0

$\therefore$        x=2, y=1 and z=-3