Discussion Forum

A bomb at rest explodes into 3 parts of same mass . The momentum of two parts is -3 p $\hat{i}$ and 2p$\hat{j}$ , respectively . The magnitude of momentum of the third part is 

Answer:

Explanation:

According to the question , we can draw the following diagram. Now , the magnitude of momentum of the third part is given by

$p_{3}=\sqrt{(p_1^2)+(p_{2})^{2}}$

 $p_{3}=\sqrt{(-3p)^2)+(2p)^{2}}$

$p_{3}=\sqrt{9p^2+4p^{2}}$

$p_{3}=\sqrt{13p^{2}}$

$\therefore$     $p_{3}=\sqrt{13}p$