Discussion Forum



1)

 The equilibrium constant  for a reaction is 20. what is the value of  $\triangle G^{0}$ at 300 K ? (R=8 x 10-3 kJ)


A) 16.63 kJ/mol

B) -5.527 kJ/mol

C) -2.763 kJ/mol

D) -1.663 kJ/mol

E) None of these

Answer:

Option D

Explanation:

 Given,

 Keq =20

 temperature (T)=300 K

 R= 8 x10-3 kJ

 we have,  $\triangle G^{0}$=-2.303 x R xT x log Keq

 = $-2.303 \times8\times 10^{-3}\times\log 20\times300 (\log 20=1.301)$

   = 7.191 k J /mol