Discussion Forum



1)

 A uniform wire has length L mass M and density $\rho$  . it is under tension T and v is the speed of transverse wave along  the wire. The area of cross-section  of the wire is 


A) $\frac{T}{v^{2}\rho}$

B) $\frac{v^{2}\rho}{T^{2}}$

C) $T^{2}v^{}\rho$

D) $T^{}v^{2}\rho$

Answer:

Option A

Explanation:

 The speed of transverse wave along a wire is given by

               $v=\sqrt{\frac{T}{\mu}}$

 where $\mu$=  mass per unit length

                     = volume of unit length  x density

                      = area x density

   $\therefore$               $v=\sqrt{\frac{T}{A\rho}}\Rightarrow A=\frac{T}{v^{2}\rho}$