1) Heating a mixture of $Cu_{2}O$ and $Cu_{2}S$ will give A) $CuO+CuS$ B) $Cu+SO_{3}$ C) $Cu+SO_{2}$ D) $Cu(OH)_{2}+CuSO_{4}$ Answer: Option CExplanation:$2 Cu_{2}O+Cu_{2}S \rightarrow 6Cu+SO_{2}$ Cuprous sulphide brings about a reduction of cuprous oxide. This reaction takes place in the Bessemer converter during the metallurgy of copper.
