Answer:
Option D
Explanation:
Given, E= 10 V
$\omega$= 200 rad/s
R= 50 $\Omega$
L=400 mH
C=200 $\mu$ F
We know that,
$Z=\sqrt{R^{2}+(X_{L}-X_{c})^{2}}$
$Z=\sqrt{(50)^{2}+(80-25)^{2}}=\sqrt{(50)^{2}-(55)^{2}}$
$=\sqrt{2500+3025}$
Z= $\sqrt{5525}=74.3 \Omega$
$I= \frac{E}{Z}=\frac{10}{74.3}=0.13459 A$
$E_{L}=IX_{L}=0.13459 \times 80$
=10.76 V or 10.8 V
