Discussion Forum

 In the Freundlich  isotherm  $\left(\frac{x}{m}=k_{p}^{1/n}\right)$ plot of $\log \frac{x}{m}$ vs $\log p$, the intercepts are (where,x,m, p and k are mass of the gas, mass of adsorbent, pressure and constant  which depend on the nature of adsorbent, respectively)

Answer:

Explanation:

 For Freundlich adsorption isotherm equation

   $\frac{x}{m}=k_{p}  \frac{1}{n}$

 or     $\log \frac{x}{m}= \log k+  \frac{1}{n} \log p$

 A plot  of $\log \frac{x}{m}$ versus $\log p$  is linear  with slope = $\frac{1}{n}$  and intercept = $\log k$