Answer:
Option B
Explanation:
We have
a= side of pentagon
b= diagonal of regular pentagon

$\angle ACB= \frac{3 \pi}{5}$
$\angle ACD= \frac{3 \pi}{10} and \angle CAD=\frac{\pi}{5}$
In $\triangle ACD$
$\cos \frac{\pi}{5}=\frac{AD}{AC}\Rightarrow AD=a\cos \frac{\pi}{5}$
$2AD=2a\cos \frac{\pi}{5}\Rightarrow \frac{b}{a}=$ $2 \cos \frac{\pi}{5}$