1) The area (in square units) of the region bounded by the curve y=|sin 2x| and X-axis in [0, $2 \pi$] is A) 0 B) 1 C) 3 D) 4 Answer: Option DExplanation: Required area $A=\int_{0}^{2 \pi} | \sin 2x|dx$ $=4\int_{0}^{ \pi /2} \sin 2xdx=4\left[ -\frac{\cos 2x}{2}\right]^{\pi/2}_{0}$ = 2[-(-1-1)]=4 Hence, option (d) is correct
