Discussion Forum

A current carrying conductor obeys Ohm's law  (V= RI). If the current passing through the conductor is  $l=(5\pm0.2)$A  and voltage   developed  is  $V=(60\pm6)$ V , then find the percentage  of error is resistance, R

Answer:

Explanation:

Given, current passing through  the conductor

  $I= (5\pm0.2)A, \triangle l=0.2 A$

 Voltage developed,

 $V=(60 \pm  6) V$

 $\Rightarrow$     $\triangle V=6V$

 By Ohm's law,

   V=RI

 $R=\frac{V}{I}$

 $\therefore$    $\frac{\triangle  R}{R}=\frac{\triangle V}{V}+\frac{\triangle I}{I}$

                             =$\frac{6}{60}+\frac{0.2}{5}$

 = 0.1+0.04

  $\frac{ \triangle R}{R}=0.14$

 $\therefore$     $\frac{ \triangle R }{R} \times 100=0.14 \times$ 100=14%