Discussion Forum



1)

The bond angles of $NH_{3},NH_{4}^{+}$ and $NH_{2}^{-}$ are in the order


A) $NH_{2}^{-}$> $NH_{3}$ > $NH_{4}^{-}$

B) $NH_{4}^{+}$ > $NH_{3}$ > $NH_{2}^{-}$

C) $NH_{3}$ > $NH_{2}^{-}$ > $NH_{4}^{-}$

D) NH > $NH_{4}^{-}$ > $NH_{2}^{-}$

Answer:

Option B

Explanation:

On increases the number of lone pairs of electrons , bond angle decreases . therefore , order of bond angle is 

$NH_{4}^{+}$   >$NH_{3}$ >$NH_{2}^{-}$

 (no/p)           (one/p)           (two/p)