Discussion Forum



1)

Current in the circuit will be 

1102021944_j6.PNG


A) $\frac{4}{50}A$

B) $\frac{5}{50}A$

C) $\frac{5}{10}A$

D) $\frac{5}{20}A$

Answer:

Option B

Explanation:

Here, diode  in lower  branch is forward  and in upper branch  is reveresed  biased

$\therefore$    $i= \frac{5}{20+30}=\frac{5}{50}A$