1)

A solenoid  30 cm long is made up of winding 2000 loops of wire on an iron rod whose cross-section is $1.5 cm^{2}$. If the relative permeability of the iron is 6000. What is the self-inductance of the solenoid?


A) 1.5 H

B) 2.5H

C) 3.5 H

D) 0.5H

Answer:

Option A

Explanation:

As we know , self-inductance  of the solenoid

   $L= \frac{\mu_{r}.\mu_{0} N^{2}A}{I}$

  $= \frac{600 \times 4 \pi \times 10^{-7} \times (2000)^{2} \times (1.5)\times  10^{-4}}{0.3}$

   $=1.5H$