1)

A coil of resistance 10Ω and an inductance 5H is connected to a 100 V battery. The energy stored in the coil is 


A) 325 erg

B) 125J

C) 250erg

D) 250J

Answer:

Option D

Explanation:

Current $I=\frac{V}{R}=\frac{100}{10}=10A$

Energy , $E= \frac{1}{2}LI^{2}$

     $= \frac{1}{2}\times 5 \times (10)^{2}=250 J$