1)

The denial cell is balanced on the 125 cm length of a potentiometer. Now, the cell is short-circuited by the resistance of $2 \Omega$ and the balance is obtained at 100 cm . The internal  resistance  of the denial cell is 


A) $\frac{4}{3}\Omega$

B) $1.5 \Omega$

C) $1.25 \Omega$

D) $0.5 \Omega$

Answer:

Option D

Explanation:

Here,    $r=R\left(\frac{I_{1}}{I_{2}}-1\right)=2\left(\frac{125}{100}-1\right)$

$=2\left(\frac{5}{4}-1\right)=2\times\frac{1}{4}=0.05 \Omega$