Discussion Forum

An eye can detect $5 \times 10^{4}$ photons per square meter per sec of green light ($\lambda \alpha=5000Å)$ while the ear can detect $10^{-13}$W/m² . The factor by which the eye is more sensitive as a power detector the ear is close to 

Answer:

Explanation:

Energy = $\frac{12375}{5000}=2.475Ev=4 \times 10^{-19}J$

 Minimum intensity to which the eye can respond 

$I_{eye}=$(photon flux) x energu of photon

$I_{eye}=(5 \times 10^{4}) \times 4 \times 10^{-19}$

=$2 \times 10^{-14} W/m^{2}$

Now, lesser the intensity required by a detector for detection more sensitive it will  be

  $\frac{I_{ear}}{I_{eye}}=\frac{10^{-13}}{2 \times 10^{-14}}=5$