Discussion Forum



1)

Anisole  is treated with HI under two different condition         

  C+D  $\underleftarrow{HI(g)}$   $C_{6}H_{5}OCH_{3}$  $\underrightarrow{conc. HI}$  A+B

 the nature of A  to D will be


A) A and B are $CH_{3}I $and $ C_{6}H_{5}OH$ while C and D are $CH_{3}OH$ and $C_{6}H_{5}I$

B) A and B are $CH_{3}OH$ and $C_{6}H_{5}I$ , while C and D are $CH_{3}I $and $ C_{6}H_{5}OH$

C) Both A and B as wella s both C and D are $CH_{3}I $and $ C_{6}H_{5}OH$

D) A and B are $CH_{3}I $and $ C_{6}H_{5}OH$ while there is no reaction in the second case

Answer:

Option C

Explanation:

 Although in both cases products are CH3I and C6H5 OH; the two reactions follow different mechanism

$C_{6}H_{5}-O-CH_{3} $   $\underrightarrow{ HI(g)}$  $CH_{3}I +C_{6}H_{5}OH$

                                               SN 2

$C_{6}H_{5}-O-CH_{3} $   $\underrightarrow{conc. HI}$  $CH_{3}I +C_{6}H_{5}OH$

                                               SN2

Remember that during  SN 1 reaction, CH3+ is formed because  it is more stable than C6 H5+