1)

 If the nuclear radius of 27 Al is 3.6 Fermi, the approximate nuclear radius of 64Cu  in Fermi is


A) 4.8

B) 3.6

C) 2.4

D) 1.2

Answer:

Option A

Explanation:

 Nuclear radius , $r\propto A^{1/3}$

 Where A is mass number

 $\frac{r_{Cu}}{r_{Al}}=\left(\frac{A_{Cu}}{A_{Al}}\right)^{1/3}=\left(\frac{64}{27}\right)^{1/3}$

$\Rightarrow r_{Cu}=3.6\left(\frac{4}{3}\right)=4.8 Fermi$