1)

Standard entropies of X2 , Y2 and XY3 are 60, 30 and 50 JK-1 mol-1 respectively. For the reaction

$\frac{1}{2}X_{2}+ \frac{3}{2}Y_{2}\rightleftharpoons XY_{3} \triangle H = - 30KJ$ to be at equilibrium, the temperature should be


A) 750K

B) 1000K

C) 1250K

D) 500 K

Answer:

Option A

Explanation:

ΔS for the reaction,

$\frac{1}{2}X_{2}+ \frac{3}{2}Y_{2}\rightleftharpoons XY_{3}$

ΔS = 50-(30+60)= -40J

For equilibrium ΔG  = 0= ΔH - TΔS

T = ΔH/ΔS = -30000/-40 = 750K