1) A substance C4H10O yields on oxidation a compound, C4H8O which gives an oxime and a positive iodoform test. The original substance on treatment with conc. H2SO4 gives C4H8. The structure of the compound is A) $CH_{3}CH_{2}CH_{2}CH_{2}OH$ B) $CH_{3}CHOHCH_{2}CH_{3}$ C) $(CH_{3})_{3}COH$ D) $CH_{3}CH_{2}-O-CH_{2}CH_{3}$ Answer: Option BExplanation: Thus $C_{4}H_{8}O$ should be $CH_{3}COCH_{2}CH_{3}$, hence C4H10O should be $CH_{3}CHOHCH_{2}CH_{3}$
