Discussion Forum



1)

In the series of reaction

$C_{6}H_{5}NH_{2} \xrightarrow[{0-5^{\circ}C}]{NaNO_{2}/HCl}X\xrightarrow[{H_{2}O}]{HNO_{2}}Y +N_{2}+HCl$

X and Y are Respectively


A) $C_{6}H_{5}-N=N-C_{6}H_{5},C_{6}H_{5}N_2^\oplus Cl^{\ominus}$

B) $C_{6}H_{5}N_2^\oplus Cl^{-},C_{6}H_{5}-N=N-C_{6}H_{5}$

C) $C_{6}H_{5}N_2^\oplus Cl^{-},C_{6}H_{5}NO_{2}$

D) $C_{6}H_{5}NO_{2},C_{6}H_{6},$

Answer:

Option C

Explanation:

$C_{6}H_{5}NH_{2} \xrightarrow[{0-5^{\circ}C}]{NaNO_{2}/HCl}C_{6}H_{5}N_2^+ Cl^{-}\xrightarrow[{H_{2}O}]{HNO_{2}}C_{6}H_{5}NO_{2} +N_{2}+HCl$