Discussion Forum



1)

Consider the junction diode as ideal. The value of current fiowing through AB is

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A) 0 A

B) $10^{-2}$ A

C) $10^{-1}$ A

D) $10^{-3}$ A

Answer:

Option B

Explanation:

Since diode is in forward bias, so the value of current flowing through AB,

$i =\frac{ΔV}{R} = \frac{4-(-6)}{1\times10^{3}}=\frac{10}{10^{3}}$

$10^{-2}$ A