1) In the reaction, $C_{6}H_{5}OH\xrightarrow{NaOH}(A)$ $\xrightarrow[{140^0c,(4-7 atm)}]{CO_{2}}$ $(B)\xrightarrow{HCl} (C)$ the compound (C) is? A) Benzoic acid B) Salicylaldehyde C) Chlorobenzene D) Salicylic acid Answer: Option DExplanation:Treatment of sodium salt of phenol with CO2 under pressure brings about substitution of the -COOH group for the hydrogen of the ring. This is called as Kolbe's reaction
