1)

A mass of 0.5 kg moving with a speed of 1.5 m/ s on a horizontal smooth surface, collides with a nearly weightless spring of force constant k: 50N/m. The maximum compression of the spring would be

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A) 0.5m

B) 0.15m

C) 0.12m

D) 1.5m

Answer:

Option B

Explanation:

Apply the law of conservation of energy,

$\frac{1}{2}mv^{2} = \frac{1}{2}kx^{2}$

$mv^{2} = kx^{2}$ or 0.5 × (1.5)2 = 50×X2

 .'. x=0.15m